Fix sql syntax error

This commit is contained in:
Laurent Destailleur 2015-03-18 14:19:17 +01:00
parent bbef07ef3d
commit 2c61717e10

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@ -530,7 +530,7 @@ class ExtraFields
$sql.= " ".($perms?"'".$this->db->escape($perms)."'":"null").","; $sql.= " ".($perms?"'".$this->db->escape($perms)."'":"null").",";
$sql.= " '".$pos."',"; $sql.= " '".$pos."',";
$sql.= " '".$alwayseditable."',"; $sql.= " '".$alwayseditable."',";
$sql.= " '".$param."'"; $sql.= " '".$param."',";
$sql.= " ".$list; $sql.= " ".$list;
$sql.= ")"; $sql.= ")";
dol_syslog(get_class($this)."::update_label", LOG_DEBUG); dol_syslog(get_class($this)."::update_label", LOG_DEBUG);
@ -1062,7 +1062,7 @@ class ExtraFields
$object = new $InfoFieldList[0]($this->db); $object = new $InfoFieldList[0]($this->db);
$object->fetch($value); $object->fetch($value);
$out='<input type="text" class="flat" name="options_'.$key.$keyprefix.'" size="20" value="'.$object->ref.'" >'; $out='<input type="text" class="flat" name="options_'.$key.$keyprefix.'" size="20" value="'.$object->ref.'" >';
} }
/* Add comments /* Add comments
if ($type == 'date') $out.=' (YYYY-MM-DD)'; if ($type == 'date') $out.=' (YYYY-MM-DD)';